SOLUTION: how many liters of a 40% alcohol solution must be mixed with 65% solution to obtain 30 L of a 50% alcohol solution
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Question 1157806: how many liters of a 40% alcohol solution must be mixed with 65% solution to obtain 30 L of a 50% alcohol solution
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
L = 40
H = 65
T = 50
M = 30
v, volume of the H %, the 65% alcohol
M-v, volume of the L % alcohol
-
Solve for v.
Formula is
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