SOLUTION: Bruce wants to make 50 ml of an alcohol solution with a 12% concentration. He has a 10% alcohol solution and a 15% alcohol solution. The equation 0.10x + 0.15(50 - x) = 0.12(50)

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Question 1156281: Bruce wants to make 50 ml of an alcohol solution with a 12% concentration. He has a 10% alcohol solution and a 15% alcohol solution. The equation 0.10x + 0.15(50 - x) = 0.12(50) can be used to find the amount of 10% alcohol solution Bruce should use.
How much of the 10% alcohol solution should Bruce use?
mL
How much of the 15% alcohol solution should Bruce use?
mL

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39620)   (Show Source): You can put this solution on YOUR website!
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..., make 50 ml of an alcohol solution with a 12% concentration. He has a 10% alcohol solution and a 15% alcohol solution.
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If want x of the 10% alcohol, then use 50-x of the 15% alcohol.

Accounting for quantities of alcohol to give the expected amount of pure alcohol: ;




, and you can finish this.

Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

Bruce wants to make 50 ml of an alcohol solution with a 12% concentration. He has a 10% alcohol solution and a 15% alcohol solution. The equation 0.10x + 0.15(50 - x) = 0.12(50) can be used to find the amount of 10% alcohol solution Bruce should use.
How much of the 10% alcohol solution should Bruce use?
How much of the 15% alcohol solution should Bruce use?
0.10x + 0.15(50  -  x) = 0.12(50)
The given equation indicates that the 10% solution was named x
This means that the 15% solution is 50 - x, as named
.1x + .15(50 - x) = .12(50)
.1x + 7.5 - .15x = 6
.1x - .15x = 6 - 7.5
- .05x = - 1.5
x, or amount of 10% solution to mix =
Now, can you find the amount of 15% solution to mix?
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