SOLUTION: Can you help me solve this problem/
How much of a 60% orange juice drink must be mixed with 14 gallons of a 20% orange juice drink to obtain a mixture that is 50% orange juice
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Question 1153682: Can you help me solve this problem/
How much of a 60% orange juice drink must be mixed with 14 gallons of a 20% orange juice drink to obtain a mixture that is 50% orange juice
The amount of 60% orange juice drink is ____ gallons
Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39616) (Show Source): You can put this solution on YOUR website!
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How much of a 60% orange juice drink must be mixed with 14 gallons of a 20% orange juice drink to obtain a mixture that is 50% orange juice?
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v gallons of 60%
----------solve for v.
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Answer by greenestamps(13198) (Show Source): You can put this solution on YOUR website!
If a formal algebraic solution is not required, here is a method that will get you to the answer to this and many similar problems with very little effort.
Think of the problem as starting with 20% juice and adding 60% juice, stopping when the mixture is 50% juice.
50% is 3/4 of the way from 20% to 60%. (20 to 60 is 40; 20 to 50 is 30; 30/40 = 3/4.)
That means 3/4 of the mixture must be the 60% juice you are adding.
So the original 14 gallons of 20% juice is 1/4 of the mixture; that means the 3/4 of the mixture that is the added 60% juice is 3*14 = 42 gallons.
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