.
x pounds of the 70% alloy and the rest, (640-x) pounds of the 54% alloy.
Then the balance equation for the pure aluminium is
0.70x + 0.54*(640-x) = 0.65*540 pounds.
From the equation, express x and calculate
x = = 440.
ANSWER. 440 pounds of the 70% alloy and the rest, 640-440 = 200 pounds of the 54% alloy.
CHECK. 0.70*440 + 0.54*200 = 416 pound of the pure aluminium in the ingredients, and
0.65*640 = 416 pounds of the pure aluminium in the resulting alloy. ! Precisely correct !
Solved.
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It is a standard and typical mixture word problem.
There is entire bunch of introductory lessons covering various types of mixture problems
- Mixture problems
- More Mixture problems
- Solving typical word problems on mixtures for solutions
- Word problems on mixtures for antifreeze solutions
- Word problems on mixtures for alloys
- Typical word problems on mixtures from the archive
- Advanced mixture problems
- Advanced mixture problem for three alloys
- Unusual word problem on mixtures
in this site.
You will find there ALL TYPICAL mixture problems with different methods of solutions,
explained at different levels of detalization, from very detailed to very short.
A convenient place to quickly observe these lessons from a "bird flight height" (a top view) is the last lesson in the list.
Read them and become an expert in solution mixture word problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this textbook in the section "Word problems" under the topic "Mixture problems".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.