SOLUTION: How many gallons of 40% alcohol solution must be mixed with 70% solution to obtain 30 gallons of 52% alcohol solution?
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Question 1151235: How many gallons of 40% alcohol solution must be mixed with 70% solution to obtain 30 gallons of 52% alcohol solution?
Found 3 solutions by josmiceli, greenestamps, josgarithmetic:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = gallons of 40% alcohol needed
= gallons of 70% alcohol needed
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and
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18 gallons of 40% alcohol are needed
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check:
OK
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!
Here is a very different way for solving problems like this involving a mixture of two ingredients.
If you understand it, it will get you to the answer much faster, and with less effort, than the traditional algebraic method.
(1) 52% is 2/5 of the way from 40% to 70%. (40 to 70 is 30; 40 to 52 is 12; 12/30 = 2/5)
(2) That means 2/5 of the mixture is the 70% ingredient.
ANSWER:
2/5 of 30 gallons, or 12 gallons, of the 70% solution;
3/5 of 30 gallons, or 18 gallons, of the 40% solution.
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
H=70
L=30
M=30
T=52, the target percentage for the mixture
v gallons of H%
M-v gallons of L%
-
Substitute the given values and evaluate M-v.
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