SOLUTION: Today a father is twice as old as his son. In 10 years the sum of their ages will be 89 years. Let x be the sons present age. I need to translate the following situation into an

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Question 1147811: Today a father is twice as old as his son. In 10 years the sum of their ages will be 89 years. Let x be the sons present age.
I need to translate the following situation into an equation.. and I just can’t. I need help please.
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39618)   (Show Source): You can put this solution on YOUR website!
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Today a father is twice as old as his son. In 10 years the sum of their ages will be 89 years. Let x be the sons present age.
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x, son's age now

2x, the first sentence, father

, the second sentence
Answer by ikleyn(52790)   (Show Source): You can put this solution on YOUR website!
.

It is clear from the condition, that 



        today the father is twice as old as his son, and the sum of their age is 89 - 20 = 69 years.



From it, it is clear to any who can count mentally, that the son is 23 years old, while the father is 46 years old.     ANSWER


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