SOLUTION: 3,4,9,7,1,3,4,9,7,1,3...
in the sequence above, the numbers 3,4,9,7 and 1 repeat in that order, starting with 3. Whatcis the 43rd term of the sequence?
A)6
B)7
C)8
D)9
Question 1144896: 3,4,9,7,1,3,4,9,7,1,3...
in the sequence above, the numbers 3,4,9,7 and 1 repeat in that order, starting with 3. Whatcis the 43rd term of the sequence?
A)6
B)7
C)8
D)9 Found 2 solutions by ikleyn, greenestamps:Answer by ikleyn(52792) (Show Source): You can put this solution on YOUR website! .
You have the sequence 3,4,9,7,1 repeating 8 times, and then 3,4,9 in positions 41,42 and 43.
ANSWER. 9.
The repeating sequence is 5 numbers. Terms 5, 10, ..., 35, and 40 will all be the last number in the sequence, 1. Then 3 more terms to get to the 43rd term puts you at 9.
ANSWER D
Shortcut: 43/5 = 8 remainder 3, so the 43rd term is the same as the 3rd term: 9