.
Let x be the number of species A and y be the number of species B.
The most difficult part of the solution is to setup the equations.
From the condition, you have these two equation
4x + 1y = 19820 units of the first nutrient (1)
5x + 6y = 32090 units of the second nutrient (2)
These equations -- this system of equations -- is your setup.
At this point, the setup is just completed.
Now you should solve it.
You can use different methods: Substitution, Elimination, using determinants (the Cramer's rule).
For example, you may express y = 19820-4x from the first equation and then substitute it into the second
5x + 6*(19820-4x) = 32090.
It gives you x = = 4570.
Then y = 19820 - 4*4570 = 1540.
ANSWER. 4570 species of the type A and 1540 species of the type B.
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If you want to see other similar solved problems, look into the lesson
- Roses and vilolets
- Counting calories and grams of fat in combined food
in this site.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Systems of two linear equations in two unknowns".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.