Think about it ... imagine drawing the lines one at a time:



The first line has no lines to cross.  Common points = 0.



The 2nd line can cross the first line (at most) once.  Common points = 1.



The 3rd line can cross each of the first two lines once.  That's two more.  Common point count is now 1+2 = 3.



The 4th line can cross each of the first three lines once.  That's three more. Common point count is now 3+3 = 6.



B) 6 

Answer by ikleyn(52802)   (Show Source): You can put this solution on YOUR website!
 .





For other solution, see my post under this link





https://www.algebra.com/algebra/homework/word/mixtures/Mixture_Word_Problems.faq.question.1143914.html





https://www.algebra.com/algebra/homework/word/mixtures/Mixture_Word_Problems.faq.question.1143914.html







 

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