# SOLUTION: A chemist wishes to mix a 10% salt solution with a 2% salt solution to obtain 6 liters of a 4% salt solution. How many liters of each should be added?

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 Question 114391: A chemist wishes to mix a 10% salt solution with a 2% salt solution to obtain 6 liters of a 4% salt solution. How many liters of each should be added?Answer by ptaylor(2052)   (Show Source): You can put this solution on YOUR website! Let x=amount of 10% solution And y=amount of 2% solution Now we know that: x+y=6------------------eq1 0.10x+0.02y=0.04*6--------------------eq2 substitute y=6-x from eq 1 into eq2 and we get 0.10x+0.02(6-x)=0.04*6 simplify 0.10x+0.12-0.02x=0.24 subtract 0.12 from both sides 0.10x+0.12-0.12-0.02x=0.24-0.12 collect like terms 0.08x=0.12 divide both sides by 0.08 x=1.5 l----------------------amount of 10% solution needed y=6-x=6-1.5=4.5 l------------------amount of 2% solution needed CK 1.5*0.10+4.5*0.02=0.04*6 0.15+0.09=0.24 0.24=0.24 Hope this helps---ptaylor