2 < 3d - 4 < 11 ====> Add 4 to all three terms. You will get an equivalent inequality 2 + 4 < 3d < 11 + 4 6 < 3d < 15 Divide by 3 both sides. You will get an equivalent inequality 2 < d < 5. The solutions in integer numbers are d= 3 and d= 4. They are the only solutions. ANSWER. There are exactly two integer numbers satisfying given inequality.