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Let x be the number of dimes; then the number of nickels is 48-x.
The "money" equation (also called "the value equation") is
10x + 5*(48-x) = 390 cents.
Solve for x
10x + 240 - 5x = 390
10x - 5x = 390 - 240
5x = 150
x = 150/5 = 30.
Thus Ann has 30 dimes. The rest 48-30 = 18 coins are nickels.
30-18 = 12.
ANSWER. There are 12 more dimes than nickels.
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If you want to learn on how to solve coin problems, look into the lesson on this subject that were written specially for you:
- Coin problems
- More Coin problems
- Solving coin problems without using equations
- Kevin and Randy Muise have a jar containing coins
- Typical coin problems from the archive
- Three methods for solving standard (typical) coin word problems
- More complicated coin problems
- Solving coin problems mentally by grouping without using equations
- Santa Claus helps solving coin problem
- Non-typical coin problems
- OVERVIEW of lessons on coin word problems
You will find there the lessons for all levels - from introductory to advanced,
and for all methods used - from one equation to two equations and even without equations.
A convenient place to quickly observe these lessons from a "bird flight height" (a top view) is the last lesson in the list.
Read them and become an expert in solution of coin problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Coin problems".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.