SOLUTION: Given the arithmetic sequence x,y,30,z,f. Find x+y+z+f? A)60 B)80 C)120 D)130

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Question 1143271: Given the arithmetic sequence x,y,30,z,f. Find x+y+z+f?
A)60
B)80
C)120
D)130

Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!
Let the common difference be d. Then these equations are true,
so add all the left sides and all the right sides:

                y = 30-d
                x = 30-2d
                z = 30+d
                f = 30+2d
-------------------------
          y+x+z+f = 120

Notice that there are lots of different possibilities for x,y,z,f.

For example the arithmetic sequence could be 

10 20 30 40 50, which have sum 120 with d=10, or

20 25 30 35 40, which also have sum 120 with d=5, or 

54 42 30 18 6, which also have sum 120 with d=-12, or any of
an infinite number of possible arithmetic sequences.  But the
sum will always be 120.  That's interesting!

Edwin

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