SOLUTION: Suppose that one solution is 50% alcohol and another solution is 80% alcohol. HOw many liters of each solution should be mixed to make 10.5 liters of a 70% alcohol solution?

SOLUTION: Suppose that one solution is 50% alcohol and another solution is 80% alcohol. HOw many liters of each solution should be mixed to make 10.5 liters of a 70% alcohol solution?

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Question 114007: Suppose that one solution is 50% alcohol and another solution is 80% alcohol. HOw many liters of each solution should be mixed to make 10.5 liters of a 70% alcohol solution?
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
.8x+.5(10.5-x)=10.5*.7
.8x+5.25-.5x=7.35
.3x=7.35-5.25
.3x=2.1
x=2.1/.3
x=7 liters of 80% are needed.
10.5-7=3.5 liters of 50% are needed.
proof
.8*7+.5*3.5=7.35
5.6+1.75=7.35
7.35=7.35
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