.
This problem is easy to solve.
40 milliliters of the 5% salt solution contain 40*0.05 = 2 grams of dissolved salt.
You want to dilute it to 2% concentration by adding pure water.
Let new volume after adding pure water be W milliliters.
You want the concentration = be equal to 2%, i.e. 0.02:
= 0.02.
It implies W = = 100 milliliters.
So, the new volume should be 100 milliliters.
It means that you must add 100-40 = 60 milliliters of pure water to get your goal. ANSWER
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There are more formal algebra method to solve this problem.
But I specially wrote this version to show you that the problem is REALLY SIMPLE.
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There is entire bunch of introductory lessons covering various types of mixture problems
- Mixture problems
- More Mixture problems
- Solving typical word problems on mixtures for solutions
- Word problems on mixtures for antifreeze solutions
- Word problems on mixtures for alloys
- Typical word problems on mixtures from the archive
- Advanced mixture problems
- Advanced mixture problem for three alloys
in this site.
You will find there ALL TYPICAL mixture problems with different methods of solutions,
explained at different levels of detalization, from very detailed to very short.
Read them and become an expert in solution mixture word problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this textbook in the section "Word problems" under the topic "Mixture problems".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.