SOLUTION: I have food grade hydrogen peroxide that requires you to make a mixture of 11% water and 3% hydrogen peroxide. How much would that be in ounces say 10 ounces. How would I measure 3
Algebra.Com
Question 1136322: I have food grade hydrogen peroxide that requires you to make a mixture of 11% water and 3% hydrogen peroxide. How much would that be in ounces say 10 ounces. How would I measure 3% of 10 ounces
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
---
I have food grade hydrogen peroxide that requires you to make a mix
---
Who?
---
make a mixture of 11% water and 3% hydrogen peroxide. How much would that be in ounces say 10 ounces.
---
What else is in the mixture you want to make? What is the concentration of the "food grade" Hydrogen Peroxide? If only the two materials, then 11% water means 89% of the "food grade" material; and if 3% Hydrogen Peroxide, then you need to know the concentration of the food grade Hydrogen Peroxide.
RELATED QUESTIONS
If you have a mixture of 1 oz. of 35% hydrogen peroxide, how much pure water would you... (answered by ankor@dixie-net.com)
I have a 50% solution of hydrogen peroxide and I want to make 1000mls of 30% hydrogen... (answered by mananth,jorel1380)
How much hydrogen peroxide 6% solution will you need to make 300ml of hydrogen peroxide... (answered by richwmiller)
A nurse wishes to prepare a 15-ounce topical antiseptic solution containing 3% hydrogen... (answered by josmiceli)
I am stuck on this math word problem.
It states: you need to make a 600mL solution of... (answered by KMST)
A hair dye is made by blending a 8% hydrogen peroxide solution and a 3% hydrogen peroxide (answered by checkley77)
A hair dye is made by blending a 9% hydrogen peroxide solution and a 3% hydrogen peroxide (answered by Alan3354,josgarithmetic)
A hair dye is made by blending a 8% hydrogen peroxide solution and a 3% hydrogen peroxide (answered by greenestamps)
How much stock solution of hydrogen peroxide 8% will you need to make 320ml of hydrogen... (answered by richwmiller)