SOLUTION: A chemist has three different acid solutions. The first acid solution contains
20%
acid, the second contains
30%
and the third contains
75%
.He wants to use all three solu
Algebra.Com
Question 1130773: A chemist has three different acid solutions. The first acid solution contains
20%
acid, the second contains
30%
and the third contains
75%
.He wants to use all three solutions to obtain a mixture of 48
liters containing
50%
acid, using 2
times as much of the
75%
solution as the 30%
solution. How many liters of each solution should be used?
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
Not like that. You know how to present your exercise problem.
A very similar example was recently solved thoroughly.
Your current example problem #1130773 answer:
12 liters of 20%
12 liters of 30%
24 liters of 75%
RELATED QUESTIONS
A chemist has three different acid solutions. The first acid solution contains
25
%... (answered by ikleyn)
A chemist has three different acid solutions. The first acid solution contains 15% acid,... (answered by ikleyn,josgarithmetic)
a chemist has three different acid solutions. The first acid solution contains 20% acid,... (answered by josgarithmetic)
A chemist has three different acid solutions. The first acid solution contains 20% acid,... (answered by ankor@dixie-net.com)
A chemist has three different acid solutions. The first acid solution contains 20% acid... (answered by josgarithmetic)
A chemist has three different acid solutions. The first acid solution contains 20% acid,... (answered by josgarithmetic,ikleyn)
A chemist has three different acid solutions. The first acid solution contains 15% acid,... (answered by ankor@dixie-net.com,MathTherapy,Alan3354,greenestamps)
A chemist has three different acid solutions. The first acid solution contains 15% acid,... (answered by josgarithmetic,greenestamps)
A chemist has three different acid solutions. The first acid solution contains 15 % acid, (answered by stanbon,josmiceli)