SOLUTION: A chemist has three different acid solutions. The first acid solution contains 25% acid, the second contains 35% ACID, and the third contains
65%. He wants to use all three solut
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Question 1130639: A chemist has three different acid solutions. The first acid solution contains 25% acid, the second contains 35% ACID, and the third contains
65%. He wants to use all three solutions to obtain a mixture of 102 liters containing 40% acid, using 2 times as much of the 65% solution as the 35% solution. How many liters of each solution should be used?
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
x of 25%
y of 35%
z of 65%
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He wants to use all three solutions to obtain a mixture of 102 liters containing 40% acid,
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Accounting for the desired percentages and amount of pure acid
Simplify this pure-acid equation.
divide both sides by 5,
Simpler system in variables x and y:
.
.
You should get, if continue with Elimination Method,
From that you should find that .......
and .
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