SOLUTION: what quantity of pure acid must be added to 300mL of a 50% acid solution to produce a 60% acid solution?

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Question 1123843: what quantity of pure acid must be added to 300mL of a 50% acid solution to produce a 60% acid solution?
Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.
Let x be the quantity under the question.


Then your equation is


0.5*300 + x = 0.6*(x+300)


stating that the pure acid amount is the same in ingredients and in the mixture.


x =  = 75 mL.


Check.  0.5*300 + 75 = 225 mL of the pure acid.

        0.6*(300+75) = 225 mL of the pure acid.    ! Correct !

Solved.

--------------------

It is a standard and typical mixture problem.

For introductory lessons covering various types of mixture word problems see
    - Mixture problems
    - More Mixture problems
    - Solving typical word problems on mixtures for solutions
    - Typical word problems on mixtures from the archive
in this site.

You will find there ALL TYPICAL mixture problems with different methods of solutions,
explained at different levels of detalization,  from very detailed to very short.

Read them and become an expert in solution mixture word problems.

Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook in the section "Word problems" under the topic "Mixture problems".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.


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