SOLUTION: How man liters of 60% alcohol solution must be added to 20 liters of 10% alcohol solution to produce 40% alcohol solution.
Algebra.Com
Question 1123627: How man liters of 60% alcohol solution must be added to 20 liters of 10% alcohol solution to produce 40% alcohol solution.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
How man liters of 60% alcohol solution must be added to 20 liters of 10% alcohol solution to produce 40% alcohol solution.
--------
s = amount of 60%
t = amount of 10%
--------------
s*60 + 20*10 = (s+20)*40
RELATED QUESTIONS
How many liters of a 70% alcohol solution must be added to 50 liters of a 40% alcohol... (answered by fractalier)
How many liters of a 70% alcohol solution must be added to 50 liters of a 40% alcohol... (answered by jorel555)
How many liters of a 70% alcohol solution must be added to 50 liters of a 40% alcohol... (answered by josgarithmetic,MathTherapy)
How many liters of 80% alcohol solution must be added to 20 liters of 90% alcohol... (answered by mananth,jsmallt9)
How many liters of a 70% alcohol must be added to 50 liters of a 40% alcohol solution to... (answered by nerdybill)
How much pure alcohol must be added to a mixture of 12 liters of alcohol and 30 liters of (answered by josgarithmetic)
How much pure alcohol must be added to a mixture of 12 liters of alcohol and 30 liters of (answered by TimothyLamb,josgarithmetic)
How much pure alcohol must be added to a mixture of 12 liters of alcohol and 30 liters (answered by macston)
How much pure alcohol must be added to a mixture of 12 liters of alcohol and 30... (answered by Theo)