SOLUTION: Soybean meal is 16% protein; cornmeal is 8% protein. How many pounds of each should be mixed together in order to get 320-lb mixture that is 11% protein? How many pounds of the cor
Question 1120183: Soybean meal is 16% protein; cornmeal is 8% protein. How many pounds of each should be mixed together in order to get 320-lb mixture that is 11% protein? How many pounds of the cornmeal should be in the mixture? Found 3 solutions by josgarithmetic, MathTherapy, greenestamps:Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website! x of 16% protein
320-x of the 8% protein
Solve and then find ... Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
Soybean meal is 16% protein; cornmeal is 8% protein. How many pounds of each should be mixed together in order to get 320-lb mixture that is 11% protein? How many pounds of the cornmeal should be in the mixture?
Let the amount of protein in CORNMEAL be E
Then amount of protein in soybean = 320 - E
We then get: .08E + .16(320 - E) = .11(320)
Solve this for E, the amount of protein in cornmeal, which is what was asked for.
Here is a quick way to solve mixture problems like this involving must two ingredients.
See if it makes sense to you.... You will get the answer in a fraction of the time required for the formal algebraic solution shown by the other tutors.
(1) 11% is 3/8 of the way from 8% to 16%.
(2) Therefore 3/8 of the mixture must be the 16% ingredient.
Answer: 3/8 of the mixture -- 3/8 of 320 pounds = 120 pounds -- is the 16% protein soybean meal; the other 5/8 of the mixture -- the other 200 pounds -- is the 8% protein cornmeal.