SOLUTION: If Drink A contains 21% juice concentrate and Drink B contains 36% juice concentrate. How much of each solution should be mixed in order to create 125 milliliters of a solution tha

Question 1118927: If Drink A contains 21% juice concentrate and Drink B contains 36% juice concentrate. How much of each solution should be mixed in order to create 125 milliliters of a solution that contains 33% juice concentrate?
Answer by ikleyn(52781) (Show Source): You can put this solution on YOUR website!
.
In form of two equations it is

        x +     y = 125            (1)     (milliliters; total volume)
    0.21x + 0.36y = 0.33*125       (2)     (x= volume of the drink A;  y = volume of the drink B).


    Solve by any method.

or in form of ONE equation

    0.21x + 0.36*(125-x) = 0.33*125.


    Simplify and solve this single equation for single unknown.


    0.21x + 0.36*125 - 0.36x = 0.33*125

    -0.15x = 0.33*125 - 0.36*125

    -0.15x = -0.03*125  ====>  x =  = 25.


Answer.  25 mL of the drink A should be mixed with  (125-25) = 100 mL of the drink B.

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    - More Mixture problems
    - Solving typical word problems on mixtures for solutions
    - Typical word problems on mixtures from the archive
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The referred lessons are the part of this textbook in the section "Word problems" under the topic "Mixture problems".

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