SOLUTION: the product of three consecutive positive integers is eight times their sum.what is the sum of their squares

SOLUTION: the product of three consecutive positive integers is eight times their sum.what is the sum of their squares

Algebra.Com

Question 1117829: the product of three consecutive positive integers is eight times their sum.what is the sum of their squares
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
POSITIVE integers, n-1, n, n+1

-

n=0 will not work according to the description.

Sum Of Their Squares:

RELATED QUESTIONS
the product of three consecutive positive intergers is 8 times their sum. What is the sum (answered by stanbon)

The product of three positive consecutive integers is 15 times their sum find the three... (answered by CubeyThePenguin)

if the product of three consecutive positive integers is equal to their sum than what woe (answered by Edwin McCravy)

The product of three positive, consecutive odd integers is 15 times their sum. What are... (answered by Alan3354)

Find three consecutive positive even integers such that the sum of their squares is... (answered by Alan3354)

Find three consecutive positive odd integers such that the sum of their squares is... (answered by ramkikk66,mananth,Alan3354)

1) the sum of the squares of 2 consecutive positive odd number is 103 greater than their... (answered by josgarithmetic)

the product of two consecutive positive odd integers is one less than three times their... (answered by mananth)

The product of two consecutive positive odd integers is one less than three times their... (answered by Deina)