.
pure acid amount + pure acid amount = total pure acid amount
0.02*10 + 0.16*x = 0.12*(10+x) <<<---=== it is your balance equation; x is the amount (in liters) of the 16% solution.
0.02*10 + 0.16x = 0.12*10 + 0.12*x
0.16*x - 0.12*x = 0.12*10 - 0.02*10
(0.16 - 0.12)*x = 0.12*10 - 0.02*10
x = = 25.
Answer. 25 liters of the 16% solution should be added.
Check. = 0.12 = 12% of concentration of the final mixture. ! Correct !
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It is a standard and typical mixture problem.
For introductory lessons covering various types of mixture word problems see
- Mixture problems
- More Mixture problems
- Solving typical word problems on mixtures for solutions
- Typical word problems on mixtures from the archive
in this site.
You will find there ALL TYPICAL mixture problems with different methods of solutions,
explained at different levels of detalization, from very detailed to very short.
Read them and become an expert in solution mixture word problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this textbook in the section "Word problems" under the topic "Mixture problems".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.