SOLUTION: You need 495 mL of a 20% alcohol solution. On hand, you have a 45% alcohol mixture. How much of the 45% alcohol mixture and pure water will you need to obtain the desired solution?

SOLUTION: You need 495 mL of a 20% alcohol solution. On hand, you have a 45% alcohol mixture. How much of the 45% alcohol mixture and pure water will you need to obtain the desired solution?

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Question 1114807: You need 495 mL of a 20% alcohol solution. On hand, you have a 45% alcohol mixture. How much of the 45% alcohol mixture and pure water will you need to obtain the desired solution?

Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
https://www.algebra.com/my/Mixtures%3A-All-in-Symbols.lesson?content_action=show_dev
https://www.algebra.com/my/Mixtures%3A-All-in-Symbols.lesson?content_action=show_dev

x, amount of 45% alcohol
495-x, amount of water
495, amount of final resulting solution

This is all you need:

Note that the water contains 0% alcohol.
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