SOLUTION: You have one type of candy that sells for $4.30/lb and another type of candy that sells for $9.10/lb. You would like to have 43.2 lbs of a candy mixture that sells for $8.10/lb. Ho

Question 1111650: You have one type of candy that sells for $4.30/lb and another type of candy that sells for $9.10/lb. You would like to have 43.2 lbs of a candy mixture that sells for $8.10/lb. How much of each candy will you need to obtain the desired mixture
Found 2 solutions by ikleyn, amalm06:
Answer by ikleyn(52798)   (Show Source): You can put this solution on YOUR website!
.
Ooo, candies . . . lovely product . . .

Let x = the amount of $4.30 candy (in pounds). Then the amount of $9.10 candy to mix with is, OBVIOUSLY, (43.2-x) pounds. Then your "money" equation is 4.30*x + 9.10*(43.2-x) = 8.10*43.2 dollars. The setup is completed. Now you should solve the equation to get x. It is just technique . . .

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It is a typical mixture problem.

There is entire bunch of lessons covering various types of mixture problems
    - Mixture problems
    - More Mixture problems
    - Solving typical word problems on mixtures for solutions
    - Word problems on mixtures for antifreeze solutions
    - Word problems on mixtures for dry substances like coffee beans, nuts, cashew and peanuts
    - Word problems on mixtures for dry substances like candies, dried fruits (*)
    - Word problems on mixtures for dry substances like soil and sand
    - Word problems on mixtures for alloys
    - Typical word problems on mixtures from the archive
    - Advanced mixture problems
    - Advanced mixture problem for three alloys
    - OVERVIEW of lessons on word problems for mixtures
in this site.

Read them and become an expert in solution the mixture word problems.
Paid special attention to the lesson marked (*) in the list. It is exactly on candies . . .

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Mixture problems".

Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.

Answer by amalm06(224)   (Show Source): You can put this solution on YOUR website!
The problem can be solved quickly using the method of alligation.

Represent the $4.30 candy as x and the $9.10 candy as y.

Then 8.10-4.30=3.80 and 9.10-8.10=1. So that x/y=1/3.80

To find the quantity of x relative to the mixture:

(1/4.80)(43.2)=9 lb (Answer)

y= 43.2-9=34.2 lb (Answer)
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