SOLUTION: How many liters each of a 25% acid solution and a 65% acid solution must be used to produce 80 liters of a 45% acid solution?

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Question 1111522: How many liters each of a 25% acid solution and a 65% acid solution must be used to produce 80 liters of a 45% acid solution?
Found 3 solutions by josgarithmetic, ikleyn, greenestamps:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!

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, other quantity is 40 liters.

40 liters of 25% acid
40 liters of 65% acid

Answer by ikleyn(52784)   (Show Source): You can put this solution on YOUR website!
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0.25x + 0.65*(80-x) = 0.45*80


0.25x + 0.65*80 - 0.65x = 0.45*80


-0.4x = 0.45*80 - 0.65*80 = -0.2*80  ====>  x = 40.


Answer.  40 liters of the 25% solution and 40 liters of the 65% solution.


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There is entire bunch of introductory lessons covering various types of mixture problems
    - Mixture problems
    - More Mixture problems
    - Solving typical word problems on mixtures for solutions
    - Word problems on mixtures for antifreeze solutions
    - Word problems on mixtures for alloys
    - Typical word problems on mixtures from the archive
    - Advanced mixture problems
    - Advanced mixture problem for three alloys
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The referred lessons are the part of this textbook in the section "Word problems" under the topic "Mixture problems".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

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Be aware:   The answer by  @josgarithmetic is   W R O N G !


Answer by greenestamps(13200)   (Show Source): You can put this solution on YOUR website!


The common sense solution to this problem is that, because 45% is exactly halfway between 25% and 65%, half of the mixture must be one ingredient and half the other.

So 40 liters of each.

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