SOLUTION: how many liter of a 20% alcohol solution should be added to a 450 L solution which contain 35% alcohol so that the resulting mixture will be 30% alcohol.

Question 1110474: how many liter of a 20% alcohol solution should be added to a 450 L solution which contain 35% alcohol so that the resulting mixture will be 30% alcohol.
Found 3 solutions by stanbon, josgarithmetic, ikleyn:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
how many liters of a 20% alcohol solution should be added to a 450 L solution which contain 35% alcohol so that the resulting mixture will be 30% alcohol.
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Equation::
alch + alch = alch
0.2x + 0.35*450 = 0.3(x+450)
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20x + 35*450 = 30x + 30*450
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10x = 5*450
x = 225 L (amt. of 20% solution needed)
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Cheers,
Stan H.
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Answer by josgarithmetic(39618)   (Show Source): You can put this solution on YOUR website!
LESSON: https://www.algebra.com/my/Two-Part-Mixture-with-one-material-quantity-unknown.lesson?content_action=show_dev
https://www.algebra.com/my/Two-Part-Mixture-with-one-material-quantity-unknown.lesson?content_action=show_dev

Answer by ikleyn(52790)   (Show Source): You can put this solution on YOUR website!
.

The equation for the unknown volume "x" is this (0.35*450 + 0.2*x) = 0.3*(450+x) It says: pure alcohol amount in the mixture is the sum of the alcohol amounts in the components. 0.35*450 + 0.2*x = 0.3*450 + 0.3*x 0.35*450 - 0.3*450 = 0.3x - 0.2x 0.05*450 = 0.1x ====> x = = 225. Answer. 225 liters of the 20% alcohol solution should be added.

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There is entire bunch of introductory lessons covering various types of mixture problems
    - Mixture problems
    - More Mixture problems
    - Solving typical word problems on mixtures for solutions
    - Word problems on mixtures for antifreeze solutions
    - Word problems on mixtures for alloys
    - Typical word problems on mixtures from the archive
    - Advanced mixture problems
    - Advanced mixture problem for three alloys
in this site.

You will find there ALL TYPICAL mixture problems with different methods of solutions,
explained at different levels of detalization, from very detailed to very short.

Read them and become an expert in solution mixture word problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook in the section "Word problems" under the topic "Mixture problems".

Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.

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Be aware:   The basic equation by @josgarithmetic is   W R O N G.

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