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How much water must be added to 960ml of acid which contains 10% pure acid to obtain a solution containing 8% pure acid?
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This formulation is NOT PRECISELY CORRECT. So I fix it this way:
How much water must be added to 960 ml of acid solution which contains 10% pure acid to obtain a solution containing 8% pure acid?
Solution
= 0.08,
where x is the amount of the water under the question.
Solve this equation for x.
Your first step is to multiply both sides of the equation by (960+x).
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There is entire bunch of lessons covering various types of mixture problems
- Mixture problems
- More Mixture problems
- Solving typical word problems on mixtures for solutions
- Word problems on mixtures for antifreeze solutions
- Word problems on mixtures for alloys
- Typical word problems on mixtures from the archive
- Advanced mixture problems
- Advanced mixture problem for three alloys
in this site.
You will find there ALL TYPICAL mixture problems with different methods of solutions,
explained at different levels of detalization, from very detailed to very short.
Read them and become an expert in solution mixture word problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this textbook in the section "Word problems" under the topic "Mixture problems".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.