SOLUTION: Mrs. Greycloud works in a lab at pharmaceutical company. She needs to make 23 liters of a 19% acid solution to test a new product. Her supplier only ships a 33% and a 10% solution.

Question 1107467: Mrs. Greycloud works in a lab at pharmaceutical company. She needs to make 23 liters of a 19% acid solution to test a new product. Her supplier only ships a 33% and a 10% solution. Mrs. Greycloud decides to make the 19% solution by mixing the 33% solution with the 10% solution. How much of the 33% solution will Mrs. Greycloud need to use?
Answer by ikleyn(52787) (Show Source): You can put this solution on YOUR website!
.

pure acid amt + pure acid amt = pure acid amt


0.33x         + 0.1*(23-x)    = 0.19*23.


Solve for x,  which is the amount of the 33% acid solution.

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There is entire bunch of introductory lessons covering various types of mixture problems
    - Mixture problems
    - More Mixture problems
    - Solving typical word problems on mixtures for solutions
    - Word problems on mixtures for antifreeze solutions
    - Word problems on mixtures for alloys
    - Typical word problems on mixtures from the archive
    - Advanced mixture problems
    - Advanced mixture problem for three alloys
in this site.

You will find there ALL TYPICAL mixture problems with different methods of solutions,
explained at different levels of detalization, from very detailed to very short.

Read them and become an expert in solution mixture word problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook in the section "Word problems" under the topic "Mixture problems".

Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.

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