SOLUTION: A scientist has two solutions, which she has labeled Solution A and Solution B. Each contains salt. She knows that Solution A is 70% salt and Solution B is 95% salt. She wa

Question 1104152: A scientist has two solutions, which she has labeled Solution A and Solution B. Each contains salt. She knows that Solution A is
70%
salt and Solution B is
95%
salt. She wants to obtain
60
ounces of a mixture that is
80%
salt. How many ounces of each solution should she use?
Found 2 solutions by greenestamps, ikleyn:
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!

(1) The traditional algebraic solution....

Use x ounces of A and (60-x) ounces of B.
The amount of salt in x ounces of A is .70(x); the amount in (60-x) ounces of B is .95(60-x); the amount of salt in the mixture is .80(60).

Write and solve the equation that says the amount of salt in the two ingredients is equal to the amount in the mixture:

I'll let you finish from there....

(2) But here is an easier way to answer this kind of "mixture" problem:

Look at the percentages of the two ingredients and of the mixture, as if on a number line.
80 is 2/5 of the way from 70 to 95. (80-70=10; 95-70=25; 10/25 = 2/5).
That 2/5 means 2/5 of the mixture must be the 95% ingredient, B.

2/5 of 60 is 24; so use 24 ounces of B and 36 ounces of A.

If you finished the solution above using the standard algebraic method, that is the answer you should have gotten.
Answer by ikleyn(52787) (Show Source): You can put this solution on YOUR website!
.
No salt solution of concentration higher than 28%.

Usually middle school students who studied/learned Science/Chemistry know it (or should/must know it). It is widely known fact.

(Educated person must know it).

Read this Wikipedia article https://en.wikipedia.org/wiki/Saline_water

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