SOLUTION: You are a lab technician and must create 250 ml of a 17% salt solution. You have available three stock solutions. You have a one liter container of a 5% salt, a 500 ml container
Algebra.Com
Question 1104005: You are a lab technician and must create 250 ml of a 17% salt solution. You have available three stock solutions. You have a one liter container of a 5% salt, a 500 ml container of a 28% salt solution, and a 400 ml container of a 40% salt solution. Show the work necessary to calculate the cheapest method of preparing the 17% salt solution if the 5% salt solution costs $28 per liter, the 28% solution costs $38 per liter, and the 40% solution costs $50 per liter. Be sure to explain in paragraph form why you have selected the amounts of each and the total cost of your selection.
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Biggest problem is that 40% salt solution. Impossible.
40% salt solution is impossible.
NO Answer, UNLESS YOU JUST WANT TO IGNORE WHAT IS PHYSICALLY POSSIBLE.
RELATED QUESTIONS
You are a lab technician and need to put together 13 ounces of a 10.64% salt solution.... (answered by checkley77)
If you have 500 ml of 28% salt-solution, how many milliliters of it should you mix with... (answered by rothauserc)
can someone help me please with this problem
To set up a chemistry lab experiment,... (answered by lwsshak3)
You have in stock 50% solution and 30% solution? How much is each you need to create a... (answered by Alan3354)
you need 25 ml 2% salt solution and you have 100 ml 5% salt solution. how much stock... (answered by lwsshak3)
You are a lab assistant for Dr. Shay. In the lab, he has two solutions. Solution A is a... (answered by TimothyLamb)
you need to prepare a 30 ml solution of a 1.6 syrup solution . You have on hand a 50%... (answered by josgarithmetic)
A lab technician has 680 ml of a solution of water and 3% acid. How many milliliters are... (answered by josgarithmetic)
You need to prepare a 47 mL of a 24% syrup/soda “prescription”. To do this, you can use... (answered by ikleyn,mananth,greenestamps)