.
Let X = "How many liters of 5% solution should he use".
Your basic equation is THIS:
= 0.1
The numerator is the amount of the pure acid in the mixture, in liters.
The denominator is the total liquid volume, in liters
So, the ratio on the left side of the equation is the concentration of the acid in the mixture.
This concentration must be 10%, which is 0.1, so the equation is.
To solve the equation, multiply both sides by (X+10). You will get
0.05*X + 2 = 0.1*(X+10),
0.05X + 2 = 0.1X + 1 ====> 2 - 1 = 0.1X - 0.05X ====> 1 = 0.05X ====> X = = 20.
Answer. Xavier must use 20 liters of the 5% acid solution.
Check. = 0.01, the correct concentration.
Solved.
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There is entire bunch of introductory lessons covering various types of mixture problems
- Mixture problems
- More Mixture problems
- Solving typical word problems on mixtures for solutions
- Word problems on mixtures for antifreeze solutions
- Word problems on mixtures for alloys
- Typical word problems on mixtures from the archive
in this site.
Read them and become an expert in solution mixture word problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this textbook in the section "Word problems" under the topic "Mixture problems".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.