SOLUTION: If 1/4 of a mixture rice and corn was replaced by corn alone, the resulting mixture becomes 55% corn. What was the percentage of corn in the original mixture?

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Question 1097515: If 1/4 of a mixture rice and corn was replaced by corn alone, the resulting mixture becomes 55% corn. What was the percentage of corn in the original mixture?
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
100 units of corn at p percent corn

Remove 25 units of original mixture and replace with 25 units of 100% corn.

-




--------------40% corn, the original mixture
Answer by ikleyn(52787)   (Show Source): You can put this solution on YOUR website!
.
Let "M" be the the total amount/(mass) of the original mixture,

and let "x" be the fraction  of corn in the original mixture (the unknown under the question).


Then the amount of corn after replacing is  (0.75*xM + 0.25*M),
and the equation for the given corn percentage is


 = 0.55.


Cancel the factor M in the numerator and denominator. You will get


0.75x + 0.25 = 0.55  ====>  0.75x = 0.55 - 0.25 = 0.3  ====>  x =  =  = 0.4.


Answer.  The percentage of corn in the original mixture was 40%.


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