.
Let x be the volume of the 50% solution, in liters.
Then the volume of the 80% solution is (20-x) liters (since you want to have 20 liters of the resulting solution).
The pure antiseptic volume in the mixture will be
0.5x + 0.8*(20-x),
with each addend from the corresponding input ingredient.
Then the percentage equation ("concentration") will be
= 0.7 (<<<---=== 70% resulting solution).
Solve it step by step:
0.5x + 0.8*20 - 0.8x = 0.7*20
-0.3x = 0.7*20 - 0.8*20 = -0.1*20 = -2
x = = = liters.
Answer. liters of the 70% solution and the rest (20- ) = liters of the 70% solution.
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For introductory lessons covering various types of mixture word problems see
- Mixture problems
- More Mixture problems
- Solving typical word problems on mixtures for solutions
- Typical word problems on mixtures from the archive
in this site.
You will find there ALL TYPICAL mixture problems with different methods of solutions,
explained at different levels of detalization, from very detailed to very short.
Read them and become an expert in solution mixture word problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this textbook in the section "Word problems" under the topic "Mixture problems".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.