SOLUTION: how much of a 7% citric acid solution must be mixed with 35 liters of a 23% citric solution to make 14%

Question 1091942: how much of a 7% citric acid solution must be mixed with 35 liters of a 23% citric solution to make 14%
Answer by ikleyn(52781) (Show Source): You can put this solution on YOUR website!
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how much of a 7% citric acid solution must be mixed with 35 liters of a 23% citric solution to make 14% ?
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0.07x + 0.23*35 = 0.14*(x+35).


x = "how much of a 7% citric acid solution must be mixed with 35 liters of a 23% citric solution to make 14%" solution.


Simplify and solve for x.
It is just arithmetic.

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There is entire bunch of introductory lessons covering various types of mixture problems
    - Mixture problems
    - More Mixture problems
    - Solving typical word problems on mixtures for solutions
    - Word problems on mixtures for antifreeze solutions
    - Word problems on mixtures for alloys
    - Typical word problems on mixtures from the archive
in this site.

Read them and become an expert in solution mixture word problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook in the section "Word problems" under the topic "Mixture problems".

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