SOLUTION: Find the amount of a 12% saline solution that should be added to 80cc of a 22% saline solution in order to have a 16% solution

Question 1090245: Find the amount of a 12% saline solution that should be added to 80cc of a 22% saline solution in order to have a 16% solution
Answer by ikleyn(52786) (Show Source): You can put this solution on YOUR website!
.

Let x be that amount under the question, in cubic centimeters.

Then you have this equation

0.12x + 0.22*80 = 0.16*(80+x),

which represents the salt mass balasnce.


To solve the equation, multiply its both sides by 100, to get it easier. You will get

12x + 22*80 = 16*80 + 16x,

22*80 - 16*80 = 16x - 12x,

4x = 6*80  ====>  x =  = 6*20 = 120.


Answer.  120 cc of the 12% saline solution must be added.

Solved.

There is a bunch of introductory lessons covering various types of mixture problems
    - Mixture problems
    - More Mixture problems
    - Solving typical word problems on mixtures for solutions
    - Word problems on mixtures for antifreeze solutions
    - Word problems on mixtures for alloys
    - Typical word problems on mixtures from the archive
in this site.

Read them and become an expert in solution the mixture word problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook in the section "Word problems" under the topic "Mixture problems".

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