SOLUTION: River's chemistry class is doing an experiment in which the students create a 30% hydrochloric acid mixture by mixing a certain amount of 25% solution with a different amount of 50
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Question 1088504: River's chemistry class is doing an experiment in which the students create a 30% hydrochloric acid mixture by mixing a certain amount of 25% solution with a different amount of 50% solution. The amount of 25% solution used is 20 liters less than 5 times the amount of 50% solution used. How much of the 25% solution and the 50% solution are needed in all?
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
Let n be the amount of 50% solution to be used. Then the 25% solution would be 5n-20. So:
.50n+.25(5n-20)=.30(n+5n-20)
.50n+1.25n-5=.30n+1.5n-6
.05n=1
n=20
They need 20 liters of 50% solution and 80 liters of 25% solution
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