.
Let x be the amount (the volume in milliliters) of the 5% solution to be mixed.
Then the volume of the 1% solution is 100-x milliliters.
Then your "concentration" equation is
= 0.02,
or, equivalently,
100-x + 5*x = 200,
which implies
4x = 100 ----> x = = 25.
Answer. 25 milliliters of the 5% solution must be mised with 100-25 = 75 milliliters of the 1% solution.
There is entire bunch of introductory lessons covering various types of mixture problems
- Mixture problems
- More Mixture problems
- Solving typical word problems on mixtures for solutions
- Word problems on mixtures for antifreeze solutions
- Word problems on mixtures for alloys
- Typical word problems on mixtures from the archive
in this site.
Read them and become an expert in solution the mixture word problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this textbook in the section "Word problems" under the topic "Mixture problems".