SOLUTION: A chemical store room has a 90% acid solution and 40% solution. How many CENTILITERS of the 90% solution should be added to 50 CENTILITERS of the 40% solution to yield up a 50% sol

Question 1086552: A chemical store room has a 90% acid solution and 40% solution. How many CENTILITERS of the 90% solution should be added to 50 CENTILITERS of the 40% solution to yield up a 50% solution?
p.s. i caps the centiliters for clearer comprehension. Thank you sir/maam tutors! :)
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Let x = amount of the 90% acid solution (in centiliters)

We have 50 centiliters of the 40% solution.
This means we have 0.4*50 = 20 centiliters of pure acid

We're adding on x more centiliters of the 90% solution.
There are an additional 0.9*x centiliters of pure acid.

In total, we have 0.9*x+20 centiliters of pure acid.

This is out of x+50 centiliters of solution.

Divide the expressions 0.9*x + 20 over x+50 to get .
This fraction represents the ratio of pure acid to total solution.
We want this ratio to be equal to 50%.
This is because we want the final solution to be 50% acid

So set equal to 0.50 to get

------------------------------------------------------------

Now solve for x

We need 12.5 (12 and a half) centiliters of the 90% solution.
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