SOLUTION: How many kilograms of hard candy that cost $7.50 per kilogram must be mixed with 24 kilograms of jelly beans that cost $3.25 per kilogram to make a mixture that sells for $4.50 per

Question 1085078: How many kilograms of hard candy that cost $7.50 per kilogram must be mixed with 24 kilograms of jelly beans that cost $3.25 per kilogram to make a mixture that sells for $4.50 per kilogram?
Answer by ikleyn(52787) (Show Source): You can put this solution on YOUR website!
.

Your equation is

 = 4.50.


Simplify it by multiplying both sides by (x + 3.75). You will get

7.50*x + 24*3.75 = 4.50*((x+3.75).


Simplify further and solve for x, which is the amount of hard candy to be mixed, in kilograms.

There is entire bunch of lessons covering various types of mixture problems
    - Mixture problems
    - More Mixture problems
    - Solving typical word problems on mixtures for solutions
    - Word problems on mixtures for antifreeze solutions
    - Word problems on mixtures for dry substances like coffee beans, nuts, cashew and peanuts (*)
    - Word problems on mixtures for dry substances like candies, dried fruits (*)
    - Word problems on mixtures for dry substances like soil and sand
    - Word problems on mixtures for alloys
    - Typical word problems on mixtures from the archive
    - OVERVIEW of lessons on word problems for mixtures
in this site.

Read them and become an expert in solution the mixture word problems.

The closely related are the lessons marked by (*) in the list.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Mixture problems

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