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Let x be the amount (the volume, in liters) of the 25% orange juice to mix.
Then the required volume of the 5% orange juice is (20-x) liters.
The amount of the pure orange juice in the mixture is
0.25x + 0.05(20-x)
(motice that 0.25 is 25% and 0.05 is 5%).
This amount of the orange juice must be equal to 0.21*20 = 4.2 liters, as the condition requires.
So, you get this equation
0.25x + 0.05*(20-x) = 4.2.
Simplify and solve for x:
0.25x + 1.0 - 0.05x = 4.2,
0.2x = 4.2 - 1.0,
0.2x = 3.2
x = = 16.
Answer. 16 liters of the 25% juice and 20-16 = 4 liters of the 5% juice must be mixed.
Check. 0.25*16 + 0.05*4 = 4 + 0.2 = 4.2 liters of the pure juice.
Then the percentage of the pure juice in 20 liters of liquid is = 0.21 = 21%. Correct !!