SOLUTION: The length of a rectangle garden is 7ft more than twice its width. If the perimeter of the garden is 56ft, find the width of the rectangle.

Question 107611: The length of a rectangle garden is 7ft more than twice its width. If the perimeter of the garden is 56ft, find the width of the rectangle.
Answer by chitra(359) (Show Source): You can put this solution on YOUR website!
Let "l" be the length and "w" be the width of the rectangle.

So according to the given data, the perimeter = 56 units

So, by data: l = 7 + 2w and w = w

We know that the perimeter is given by P = 2l + 2w

So substituting for the values, we get:

56 = 2(7 + 2w) + 2w

56 = 14 + 4w + 2w

56 - 14 = 6w

42 = 6w

==>

==> w = 7

by back substitution we get:

l = 7 + 2w

l = 7 + 14

l = 21

Thus, the solution

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