.
Let x be the volume to be poured and replaced.
Then (40-v) is the volume of the remained original solution.
The mass of salt in (40-v) liters of the 5% solution is 0.05*(40-v).
Thus the concentration equation is
= 0.03.
Simplify and solve for v:
0.05*(40-v) = 0.03*40 ---> 2 - 0.05v = 1.2 ---> 2 - 1.2 = 0.05v ---> v = = 16.
Answer. 16 liters of the original 5% solution must be poured and replaced.
Check. = 0.03.
There is entire bunch of lessons covering various types of mixture problems
- Mixture problems
- More Mixture problems
- Solving typical word problems on mixtures for solutions
- Word problems on mixtures for antifreeze solutions
- Word problems on mixtures for alloys
- Typical word problems on mixtures from the archive
in this site.
Read them and become an expert in solution the mixture word problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this textbook in the section "Word problems" under the topic "Mixture problems".