SOLUTION: What quantity of 75 percent acid solution mist be mixed with a 30 percent solution to produce 1080ml of a 50 percent solution?

Question 1073080: What quantity of 75 percent acid solution mist be mixed with a 30 percent solution to produce 1080ml of a 50 percent solution?
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
Two Part Mixture for both quantities unknown, LESSON.
https://www.algebra.com/my/Mixtures%3A-All-in-Symbols.lesson?content_action=show_dev
https://www.algebra.com/my/Mixtures%3A-All-in-Symbols.lesson?content_action=show_dev

Two Part Mixture, example, showing the use of just a single variable
Answer by ikleyn(52786)   (Show Source): You can put this solution on YOUR website!
.
What quantity of 75 percent acid solution mist be mixed with a 30 percent solution to produce 1080 mL of a 50 percent solution?
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Let V be the volume of the 75% acid solution to be mixed. Then the volume of the 30% solution must be 1080 mL. Your governing equation is the concentration equation = 0.5. Simplify and solve it: 0.75V + 324 - 0.3V = 0.5*1080, 0.45V = 540 - 324 ---> 0.45V = 216 ---> V = = 480 mL. Answer. 480 mL of the 75% solution must be mixed with 1080-480 = 600 mL of the 50% solution.

There is entire bunch of lessons covering various types of mixture problems
    - Mixture problems
    - More Mixture problems
    - Solving typical word problems on mixtures for solutions
    - Word problems on mixtures for antifreeze solutions
    - Word problems on mixtures for alloys
    - Typical word problems on mixtures from the archive
in this site.

Read them and become an expert in solution the mixture word problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook in the section "Word problems" under the topic "Mixture problems".

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