SOLUTION: Justin needs 140 L of an 80% acid solution. he only has a 25% solution and a 95% solution though how many liters of each does he need to make the needed 140 L of 80% acid solution

Question 1072534: Justin needs 140 L of an 80% acid solution. he only has a 25% solution and a 95% solution though how many liters of each does he need to make the needed 140 L of 80% acid solution?
Answer by ikleyn(52797) (Show Source): You can put this solution on YOUR website!
.

Let x be the volume of the 25% acid solution to mix, and
let y be the volume of the 95% acid solution to mix.


Then your governing equations are


    x +      y = 140,       (1)
0.25x + 0.95*y = 0.8*140.   (2)


Simplify and solve for x and y.

There is entire bunch of lessons covering various types of mixture problems
    - Mixture problems
    - More Mixture problems
    - Solving typical word problems on mixtures for solutions
    - Word problems on mixtures for antifreeze solutions
    - Word problems on mixtures for alloys
    - Typical word problems on mixtures from the archive
in this site.

Read them and become an expert in solution the mixture word problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Mixture problems

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