SOLUTION: Use a system of equations to solve this problem. A chemist currently has two solutions of sodium chloride. One solution has a 5% concentration and the other has a 25% concentrat

Question 1069565: Use a system of equations to solve this problem.
A chemist currently has two solutions of sodium chloride. One solution has a 5% concentration and the other has a 25% concentration. The chemist needs to make 10 L of a 10% sodium chloride solution.
Let x = the amount of 5% solution.
Let y = the amount of 25% solution.

How much of each solution does the chemist need to make?
Enter your answers, as decimals, in the boxes.
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
How are the units used?
w/w or w/v ?

If as w/w, then you need to know or use or refer to

5% 1.034 g/ml 10% 1.0707 g/ml 24% 1.1804 g/ml 26% 1.1972 g/ml Middle of 24 and 26 percents should give 1.1888 g/ml for 25% solution. Refered to online, http://chemistry.mdma.ch/hiveboard/rhodium/pdf/chemical-data/prop_aq.pdf

Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
Use a system of equations to solve this problem.
A chemist currently has two solutions of sodium chloride. One solution has a 5% concentration and the other has a 25% concentration. The chemist needs to make 10 L of a 10% sodium chloride solution.
Let x = the amount of 5% solution.
Let y = the amount of 25% solution.

How much of each solution does the chemist need to make?
Enter your answers, as decimals, in the boxes.

The system of equations you need is:
Solve to get "x", or the amount of 5% solution to be mixed
Solve to get "y," or the amount of 25% solution.
**Note that the amount of the 5% solution will be 5 times the amount of the 25% solution.
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