SOLUTION: An alloy contains 80% bronze and 20% tin. An other alloy contains 85% bronze and 12% tin.find the ratio of mixing both alloys such that 15% tin should be in mixture.also find % of

Question 1068448: An alloy contains 80% bronze and 20% tin. An other alloy contains 85% bronze and 12% tin.find the ratio of mixing both alloys such that 15% tin should be in mixture.also find % of bronze .
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
An alloy contains 80% bronze and 20% tin.
An other alloy contains 85% bronze and 12% tin.
find the ratio of mixing both alloys such that 15% tin should be in mixture.
also find % of bronze .
:
Assume an amt of 120 units in the original mixture,
let x = the amt of the 2nd mixture required to obtain 15% tin
:
Write a mixture equation based on the amt of tin
.20(120) + .12x = .15(x+120)
24 + .12x = .15x + 18
24 - 18 = .15x - .12x
6 = .03x
x = 6/.03
x = 200 units of the 2nd mixture to be added to the 120 units of the original
Find the ratio of these two
= 3:5
:
The % bronze of the 2nd mixture is given as 85% and 12% tin. These do not add up to 100%, so something is wrong here
:
Anyway, if you have 15% tin you have 85% bronze

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