SOLUTION: a solution contains 5% salt. How much water should be added to 70 ounces of this solution to make 3.5% solution?

Question 1057510: a solution contains 5% salt. How much water should be added to 70 ounces of this solution to make 3.5% solution?
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39620)   (Show Source): You can put this solution on YOUR website!
Simple Dilution.

https://www.algebra.com/my/Two-Part-Mixture-with-one-material-quantity-unknown.lesson?content_action=show_dev
Answer by ikleyn(52798)   (Show Source): You can put this solution on YOUR website!
.
a solution contains 5% salt. How much water should be added to 70 ounces of this solution to make 3.5% solution?
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Let W be the volume of water to be added, in ounces. Then the total volume of liquid after adding will be 70+W ounces. The "salt" equation is = 0.035 ( 0.05 is 5%; 0.035 is 3.5% ) or, which is the same 0.05*70 = 0.035*(70+W). Simplify. First, multiply both sides by 1000: 50*70 = 35(70+W), 3500 = 2450 + 35W, 3500 - 2450 = 35W, 1050 = 35W ---> W = = 30. Answer. 30 ounces of water must be added.

There is entire bunch of lessons covering various types of mixture problems
    - Mixture problems
    - More Mixture problems
    - Solving typical word problems on mixtures for solutions
    - Word problems on mixtures for antifreeze solutions
    - Word problems on mixtures for alloys
    - Typical word problems on mixtures from the archive
in this site.

Read them and become an expert in solution the mixture word problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook in the section "Word problems" under the topic "Mixture problems".

The textbook contains many other solved word problems, as well as many other interesting and useful things.

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