SOLUTION: How much pure water must be mixed with 12L of a 40% alcohol solution to obtain a 15% alcohol solution?

Question 1053038: How much pure water must be mixed with 12L of a 40% alcohol solution to obtain a 15% alcohol solution?
Answer by ikleyn(52776) (Show Source): You can put this solution on YOUR website!
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How much pure water must be mixed with 12L of a 40% alcohol solution to obtain a 15% alcohol solution?
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The governing equation is

0.4*12 + W = 0.15*(12+W),

where W is an unknown volume of the water.

Simplify and solve for W.

For detailed solutions of various types of mixture problems see the lessons
    - Mixture problems
    - More Mixture problems
    - Solving typical word problems on mixtures for solutions
    - Word problems on mixtures for antifreeze solutions
    - Word problems on mixtures for alloys
    - Typical word problems on mixtures from the archive
in this site.

Read them and become an expert in solution the mixture word problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Mixture problems".

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